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Question

The velocity associated with a proton moving in a potential difference of 1000 V is $$\displaystyle 4.37\times { 10 }^{ 5 }\ { ms }^{ -1 }$$. If the hockey ball of mass 0.1 kg is moving with this velocity, calculate the wavelength associated with this velocity. 


Solution

The associated wavelength is obtained from de-Broglie equation.
$$\displaystyle \lambda = \frac {h}{mv} =   \frac {6.626 \times 10^{-34} }{0.1 \times 4.37 \times 10^{5} } = 1.516 \times 10^{-28} m$$

Chemistry
NCERT
Standard XI

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