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Question

The velocity associated with a proton moving in a potential difference of 1000 V is 4.37×105 ms1. If the hockey ball of mass 0.1 kg is moving with this velocity, calculate the wavelength associated with this velocity.

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Solution

The associated wavelength is obtained from de-Broglie equation.

Here

h=6.626×1034Kgm2s1

m=0.1kgv=4.37×105ms1

Substituting the above values in de broglie equation , we get


λ=hmv=6.626×10340.1×4.37×105=1.516×1028m



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