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Question

The velocity associated with a proton moving in a potential difference of 1000 V is 4.37 × 105ms1. If the hockey ball of mass 0.1 kg is moving with this velocity, calculate the wavelength associated with this velocity.


Solution

According to de Broglie’s expression,
λ=hmv
Substituting the values in the expression,
λ=6.626×1034Js(0.1kg)(4.37×105ms1)λ=1.516×1038m


Chemistry
NCERT Textbook
Standard XI

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