Question

# The velocity at the maximum height of a projectile is half of its initial velocity of projection u. Its range on the horizontal plane is

Solution

## The correct option is A If the velocity of projection is u then at the highest point body posses only u cos θ u cos θ=u2 (given)   ∴θ=60∘Now R=u2 sin(2×60∘)g=√32u2g

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