CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

The velocity at the maximum height of projectile is half of its initial velocity projection. The angle of projection is 


A
30o
loader
B
45o
loader
C
60o
loader
D
76o
loader

Solution

The correct option is D $${ 60 }^{ o }$$
Lets consider, $$u=$$ initial velocity of the projectile
$$\theta=$$ angle of projection
At maximum height,
$$velocity=ucos\theta$$
$$\dfrac{u}{2}=ucos\theta$$
$$cos\theta=\dfrac{1}{2}=0.5$$
$$\theta=cos^{-1}(0.5)$$
$$\theta=60^0$$
The correct option is C.

Physics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image