CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The velocity of a body of mass 20kg decreases from 20m/s to 5m/s in a distance of 100m . Force on the body is :

A
27.5N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
47.5N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
37.5N
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
67.5N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is D 37.5N

The equation of motion is given as,

v2=u2+2as

(5)2=(20)2+2×a×100

a=1.875m/s2

The force is given as,

F=ma

F=20×(1.875)

F=37.5N

Thus, the force on the body is 37.5N.


flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Conservative Forces and Potential Energy
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon