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Question

The velocity of an electron in a certain Bohr's orbit of H-atom bears the ratio 1:412 to the velocity of light. Calculate the value of  orbit number n .


A
3
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B
4
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C
6
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D
8
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Solution

The correct option is A 3
Given: Velocity of electron=1412×Velocity of light  ..(i)
We know,
vn=2.189×108×Zn cm/sec   ...(ii)

Equating eq. (i) and (ii), we get

2.189×108×1n=1275×(3×1010)
where, velocity of light c = 3×1010cm/s
n=2.189×108×4123×1010=3

Chemistry

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