Question

# The velocity of an electron in a certain Bohr's orbit of H-atom bears the ratio 1:412 to the velocity of light. Calculate the value of  orbit number n .

A
3
B
4
C
6
D
8

Solution

## The correct option is A 3Given: Velocity of electron=1412×Velocity of light  ..(i) We know, vn=2.189×108×Zn cm/sec   ...(ii) Equating eq. (i) and (ii), we get 2.189×108×1n=1275×(3×1010) where, velocity of light c = 3×1010cm/s ⇒n=2.189×108×4123×1010=3Chemistry

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