The velocity of an object at $t = 0$ is ${\to v}_{0} = - 4^j m / s$ . It moves in a plane with constant acceleration $\to a = (3^i + 8^j) m / s^{2}$ . What is its velocity after $1 s$

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Solution

The correct option is B 5
using equation of motion.
$V = u + a t$

Now write the equation of motion in vector form

$a = (3 i + 8 j) m / s^{2}$
$v = - 4 j + (3 i + 8 j) 1$

As

$u = - 4 j m / s a n d t = 1 sec$

Or

$v = 3 i + 4 j$

The final velocity $= {(3^{2} + 4^{2})}^{\frac{1}{2}} = 5 m / s$

Hence, the final velocity is $5 m / s$

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