Question

# The velocity-time graph of a particle moving along a straight line in a given time interval is as shown in figure. Then speed of the particle (with increase in time starting from t=0 sec )

A
increases continuously
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B
first increases and then decreases
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C
decreases continuously
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D
first decreases and then increases
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Solution

## The correct option is D first decreases and then increasesFrom t=0 sec to t=t0 sec The slope of the graph is positive(i.e.dvdt=+ve) so, acceleration is positive and velocity is negative in this time interval. Therefore, the speed of the particle will decrease first. After t=t0 sec both acceleration as well as velocity are positive so, the speed will increase after t=t0 sec. Hence speed of the particle will decrease first and then increases.

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