Question

# The velocity-time graph of a stone thrown vertically upward with an initial velocity of $$30\ m/s$$ is shown in the figure. The velocity in the upward direction is taken as positive and that in the downward direction as negative. What is the maximum height to which the stone rises? ($$g=9.5$$)

A
30 m
B
45 m
C
60 m
D
90 m

Solution

## The correct option is B 45 mAt minimum height $$v=0$$$$\therefore$$ max height = area of $$\triangle$$ OAB$$H=\dfrac{1}{2}\times 3\times 30=45\ m$$Physics

Suggest Corrections

0

Similar questions
View More

People also searched for
View More