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Question

The velocity – time graph of a stone thrown vertically upward with an initial velocity of 30 ms1 is shown in the figure below. The velocity in the upward direction is taken as positive and that in downward direction as negative. What is the maximum height to which the stone rises?



A
30 m
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B
45 m
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C
60 m
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D
90 m
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Solution

The correct option is B 45 m
Given u=30 ms1

From figure above, the acceleration a = slope of line AB =30 ms13 s=10 ms2
The maximum height is reached when final velocity v=0. Using the value of u,v and a in relation
v2u2=2as, we get
0302=2×(10)×s
or s=30×3020=45 m
Hence the correct choice is (b).

Physics

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