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Question

The velocity $$(v)$$ of a particle moving along $$x-$$axis varies with its position $$x$$ as shown in figure. The acceleration $$(a)$$ of particle varies with position $$(x)$$ as
806129_00891845c62d4dc387aedcad009d5b03.png


A
a2=x+3
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B
a=2x2+4
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C
2a=3x+5
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D
a=4x8
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Solution

The correct option is D $$a = 4x - 8$$
As shown in the given figure
equation of velocity and displacement is
$$V=-2x+4$$
acceleration $$a=V\cfrac { dv }{ dx } \\ \quad =(-2x+4)(-2)\\ \quad =4x-8$$


Physics

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