Question

The velocity (v) of a particle that moves in the positive x-direction varies with its position (x) as shown in the figure. The acceleration of the particle at $x=5$ m is nearly:

• A. $10m{s}^{-2}$
• B. $9.4m{s}^{-2}$
• C. $7.4m{s}^{-2}$
• D. $-1.25m{s}^{-2}$

Answer 1

The correct option is B $9.4m{s}^{-2}$

We know, by Newton's law of motion,

$v^2-u^2=2as$.....................(1)

so,$v=5m/s$

$u=10m/s$

$x_1=3m$

$x_2=7m$

$s=x_2-x_1$=7-3=4m

Using (1),

$2.a.4=5^2-{10}^2$

solving, we get, a=$-9.4m/s^2$

Answer is B.