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Question

The velocity (v) of a particle that moves in the positive x-direction varies with its position (x) as shown in the figure. The acceleration of the particle at x=5 m is nearly:
1169266_3fd8d524437842fa9a82cd9d2edbc1dc.png

A
10ms2
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B
9.4ms2
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C
7.4ms2
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D
1.25ms2
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Solution

The correct option is B 9.4ms2
We know, by Newton's law of motion,
v2u2=2as.....................(1)
so,v=5m/s
u=10m/s
x1=3m
x2=7m
s=x2x1=7-3=4m
Using (1),
2.a.4=52102
solving, we get, a=9.4m/s2
Answer is B.


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