Question

# The vertices of a ΔABC are A (4, 6), B (1, 5) and C (7, 2). A line is drawn to intersect sides AB at D, such that AD/AB= 14 . Calculate the area of the ΔADC.

Solution

## So D is the point which divides AB in the ratio 1 : 3. Using section formula we get the coordinates of D(3.25,5.75) Area of a triangle =  12[  x1(y2  - y3) +   x2(  y3 -   y1) + x3(y1 - y2)]                             = 1.875 Mathematics

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