The vertices of a ΔABC are A (4, 6), B (1, 5) and C (7, 2). A line is drawn to intersect sides AB at D, such that AD/AB= 14 . Calculate the area of the ΔADC.
So D is the point which divides AB in the ratio 1 : 3.
Using section formula we get the coordinates of D(3.25,5.75)
Area of a triangle = 12[ x1(y2 - y3) + x2( y3 - y1) + x3(y1 - y2)]