The vertices of a hyperbola are (2, 0), (–2, 0) and the foci are (3, 0), (–3, 0). The equation of the hyperbola is

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B

$C e n t r e = (0, 0), a = 2, a e = 3 \Rightarrow e = \frac{3}{2}$

$b^{2} = a^{2} (e^{2} - 1) = a^{2} e^{2} - a^{2} = 9 - 4 = 5$

equation of the hyperbola is $\frac{x^{2}}{4} - \frac{y^{2}}{5} = 1$

Suggest Corrections

Similar questions

Find the equation of the hyperbola satisfying the give conditions: Vertices (±2, 0), foci (±3, 0)

Find the equation of the hyperbola satisfying the given conditions,

Vertices $(\pm 2, 0), f o c i (\pm 3, 0)$

(- 2, 0)

(2, 0)

(- 3, 0),

(\pm 3, 0)

(\pm 2, 0)

(- 2, 0)

(2, 0)

(- 3, 0),

Join BYJU'S Learning Program