Question

The voltage time $(V-t)$ graph for triangular wave having peak value $V_0$ is as shown in figure. The average value of voltage V in time interval from t=0 to T is

Answer 1

average value of voltage =
$\frac{\text{Area under voltage - time curve}}{\text{Time interval}}$

area above time axis is taken +ve and area below time axis is taken -ve

if area from t = 0 to t =T/2 is A, area from t = T/2 to t = T is -A

(congruent trinangles)

so total area under curve from t =0 to t= T is (A-A)= 0

So, the average value of voltage for complete cycle from t = 0 to T is 0

FINAL ANSWER : (a)