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Question

The volume occupied by $$17.75 \: g$$ $$  \: of \: Cl_2$$, at S.T.P is:


A
5.6 litre
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B
11.2 litre
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C
22.4 litre
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D
44.8 litre
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Solution

The correct option is C 5.6 litre
As we know, 
one mole of each gas occupies 22.4-litre volume at STP.

Here,

Mole of $$Cl_2 = 17.75/71$$

volume occupies $$=17.75\times22.4/71= 5.6$$ litre

Hence, the correct option is $$\text{A}$$

Chemistry

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