Question

# The volume of a cuboidal box is $$48\ cm^{3}$$. If its height and length are $$3\ cm$$ and $$4\ cm$$ respectively, find its breadth(in cm).

Solution

## Suppose that the breadth of the box is $$b\space \mathrm{cm}$$. Volume of the cuboidal box $$=48 \space\mathrm{cm}^{3}$$ Height of the box $$=3 \space\mathrm{cm}$$ Length of the box $$=4 \space\mathrm{cm}$$ Now, volume of box $$\text{length} \times \text{breadth} \times \text{height}$$$$\Rightarrow 48=4 \times b \times 3$$$$\Rightarrow 48=12 \times b$$$$\Rightarrow b=\frac{48}{12}=4 \space\mathrm{cm}$$$$\therefore$$ The breadth of the cuboidal box is $$4 \space\mathrm{cm}$$Maths

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