The volume of $H_{2} S O_{4}$ acid ( $98 %$ by mass, d= $1.80$ g/mL) required to prepare $1$ litre of $0.1 M$ $H_{2} S O_{4}$ solution is:

16.65

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22.20

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5.55

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11.10

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Solution

The correct option is D $5.55$ mL
Given,
$M_{H_{2} S O_{4}} = \frac{98 \times 1.80}{98 \times 100} \times 1000 = 18.0$

$M_{1} V_{1} = M_{2} V_{2}$

$18.0 \times V_{1} = 1 \times 0.1$

$V_{1} = 5.55 \times 10^{- 3} L = 5.55$ mL

Hence, volume required is $5.55$ mL.

Hence, the correct option is $C$

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The volume of H2SO4 acid (98% by mass, d= 1.80 g/mL) required to prepare 1 litre of 0.1 M H2SO4 solution is:

The correct option is D 5.55 mLGiven,MH2SO4=98×1.8098×100×1000=18.0M1V1=M2V218.0×V1=1×0.1V1=5.55×10−3L=5.55 mLHence, volume required is 5.55 mL.Hence, the correct option is C

The volume of $H_{2} S O_{4}$ acid ( $98 %$ by mass, d= $1.80$ g/mL) required to prepare $1$ litre of $0.1 M$ $H_{2} S O_{4}$ solution is:

The correct option is D $5.55$ mL
Given,
$M_{H_{2} S O_{4}} = \frac{98 \times 1.80}{98 \times 100} \times 1000 = 18.0$

$M_{1} V_{1} = M_{2} V_{2}$

$18.0 \times V_{1} = 1 \times 0.1$

$V_{1} = 5.55 \times 10^{- 3} L = 5.55$ mL

Hence, volume required is $5.55$ mL.

Hence, the correct option is $C$