Question

The volume strength of $1\text{N}{H}_2{O}_2$ solution is:

• A. $11.2\text{V}$
• B. $22.4\text{V}$
• C. $1\text{V}$
• D. $5.6\text{V}$

Answer 1

The correct option is D $5.6\text{V}$

$1\text{N}$ means $1\text{g}$ equivalent weight in $1\text{L}$ solution.
$\text{Normality ~(N)}=\frac{\text{weight}}{\text{equiv. weight}}\Rightarrow 1=\frac{\text{weight}}{17}\Rightarrow \text{weight}=17\text{g}$
$2H_2{O}_2\left(g\right)\to 2H_{2}O\left(g\right)+O_2\left(g\right)$
From the reaction, we know that $68\text{g}$ of $H_2{O}_2$ gives $22.4\text{L}$ of Oxygen.
$\therefore 17\text{g}$ of $H_2{O}_2$ gives $=\frac{22.4\times 17}{68}=5.6\text{L}$ of Oxygen
So, the volume strength of $1\text{N}{H}_2{O}_2$ solution is $5.6\text{V}$.