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Question

The wavelength of the emitted radiation, if electron in hydrogen atom jumps from the third orbit to second orbit is

A
λ=365R
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B
λ=5R36
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C
λ=5R
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D
λ=R6
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Solution

The correct option is A λ=365R
Wave number, ¯v=R[1n211n22]
λ=1R[1419]
λ=365R

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