Question

The wavelength of the emitted radiation, if electron in hydrogen atom jumps from the third orbit to second orbit is

• A. $\lambda =\frac{36}{5R}$
• B. $\lambda =\frac{5R}{36}$
• C. $\lambda =\frac{5}{R}$
• D. $\lambda =\frac{R}{6}$

Answer 1

The correct option is A $\lambda =\frac{36}{5R}$

Wave number, $\overline{v}=R[\frac{1}{n_1^2}-\frac{1}{n_2^2}]$
$\Rightarrow \lambda =\frac{1}{R[\frac{1}{4}-\frac{1}{9}]}$
$\Rightarrow \lambda =\frac{36}{5R}$