The weakest oxidizing agent among the following is:

O_{3}

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F_{3}

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K M n O_{4}

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C l_{2}

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Solution

The correct option is D $C l_{2}$
$E_{O_{3} | O_{2}}^{⊖} = 2.07 V; E_{F_{2} | F^{⊖}}^{⊖} = 2.87 V$
$E_{M n O_{4}^{⊖} | M n^{2 +}}^{⊖} = 1.51 V; E_{C l_{2} | C l^{⊖}}^{⊖} = 1.36 V$
$∵ E_{C l_{2} | C l^{⊖}}^{⊖}$ is highest, $C l_{2}$ is the weakest oxidizing agent.

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