The weight of a wooden block of size $8 c m \times 8 c m \times 8 c m$ is $307.2 g .$ When it is floating in water, the height of the wooden block above water level is :

4.8 c m

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3.2 c m

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4 c m

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6 c m

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Solution

The correct option is B $3.2 c m$
As the wood is in equilibrium,
Upward buoyancy force $=$ Downward force
$\Rightarrow 8 \times 8 \times (8 - h) \times 1 (g / c m^{3}) \times g = 307.2 \times g$
$\Rightarrow 8 - h = \frac{307.2}{64}$

$\Rightarrow h = 8 - 4.8 \Rightarrow h = 3.2 c m$

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The weight of a wooden block of size 8cm×8cm×8 cm is 307.2 g. When it is floating in water, the height of the wooden block above water level is :

The correct option is B 3.2 cmAs the wood is in equilibrium, Upward buoyancy force = Downward force⇒8×8×(8−h)×1(g/cm3)×g=307.2×g⇒8−h=307.264⇒h=8−4.8⇒h=3.2 cm

The weight of a wooden block of size $8 c m \times 8 c m \times 8 c m$ is $307.2 g .$ When it is floating in water, the height of the wooden block above water level is :

The correct option is B $3.2 c m$
As the wood is in equilibrium,
Upward buoyancy force $=$ Downward force
$\Rightarrow 8 \times 8 \times (8 - h) \times 1 (g / c m^{3}) \times g = 307.2 \times g$
$\Rightarrow 8 - h = \frac{307.2}{64}$

$\Rightarrow h = 8 - 4.8 \Rightarrow h = 3.2 c m$