Question

The weight of oxalic acid that will be required to prepare a $1000mL\left(N/20\right)$ solution is :

• A. $126/100g$
• B. $63/40g$
• C. $63/20g$
• D. $126/20g$

Answer 1

The correct option is C $63/20g$

$Normality=Molarity\times n-factor$

$Normality=\frac{\text{Weight of oxalic acid}}{\text{Molecular weight}\times \text{volume (in litre)}}\times nfactor$

n- factor of oxalic acid $=2$.

Weight of oxalic acid $=\frac{1\times 126\times 1}{20\times 2}$

$=\frac{63}{20}gm$

Hence, option C is correct.