The width of each of five continuous classes in a frequency distribution is $5$ and the lower class-limit of the lowest class is $10$ . The upper class-limit of the highest class is:

15

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25

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35

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40

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Solution

The correct option is C $35$
Lower class limit $= 10$
Width of each class $= 5$
Width till the upper class limit for a frequency distribution having $5$ classes $= 5 \times 5 = 25$
Hence, the upper class limit of highest class $= 10 + 25 = 35$

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Q. The width of each of five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10 The upper class limit of the highest class is

The width of each of five continuous classes in a frequency distribution is 5 and the lower class - limit of the lowest class is 10.

Find the upper class - limit of the highest class.

Question 4
The width of each of five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10. The upper class limit of the highest class is:

A) 15
B) 25
C) 35
D) 40

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The width of each of five continuous classes in a frequency distribution is 5 and the lower class-limit of the lowest class is 10. The upper class-limit of the highest class is:

The correct option is C 35Lower class limit =10Width of each class =5Width till the upper class limit for a frequency distribution having 5 classes =5×5=25 Hence, the upper class limit of highest class =10+25=35

The width of each of five continuous classes in a frequency distribution is $5$ and the lower class-limit of the lowest class is $10$ . The upper class-limit of the highest class is:

The correct option is C $35$
Lower class limit $= 10$
Width of each class $= 5$
Width till the upper class limit for a frequency distribution having $5$ classes $= 5 \times 5 = 25$
Hence, the upper class limit of highest class $= 10 + 25 = 35$