The work done on a body is 250 J. If the force acting on the body in the direction of displacement during this interval is 12.5 N, the displacement of the body during this interval is ___ m.

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Solution

Work done = Force $\times$ displacement

Therefore,
$250 = 12.5 \times d i s p l a c e m e n t$ .
So, displacement = 20 m.

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A force of magnitude 25 N acting on a body of mass 2 kg increases its kinetic energy from 100 J to 200 J. The displacement of the body during this interval is ___m.

Q. A force of magnitude

25 N

acting on a body of mass

2 k g

doubles its kinetic energy to

200 J

. The displacement of the body during this interval is:

A force of magnitude 25 N acting on a body of mass 2 kg increases its kinetic energy from 100 J to 200 J. The displacement of the body during this interval is

___m.

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The work done on a body is 250 J. If the force acting on the body in the direction of displacement during this interval is 12.5 N, the displacement of the body during this interval is ___ m.

Work done = Force × displacement Therefore, 250=12.5×displacement. So, displacement = 20 m.

Work done = Force $\times$ displacement

Therefore,
$250 = 12.5 \times d i s p l a c e m e n t$ .
So, displacement = 20 m.