MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Octet Rule

The work done...

Question

The work done when two moles of an ideal gas is compressed from a volume of 5 m³ to 1 dm³ at 300K,under a pressure of 100kPa?

Open in App

Solution

The work done on an ideal gas is
W=p(V1-V2 )=100x1000(5-0.001)=499900 J=499.9 kJ.

Suggest Corrections

thumbs-up

22

Similar questions

Q. The work done when

2 m o l e s

of an ideal gas is compressed from a volume of

5 m^{3}

1 d m^{3}

at an initial temperature of

300 K

, under a pressure of

100 k P a

Q. What is the amount of work done when two moles of ideal gas is compressed from a volume of

1 m^{3}

10 d m^{3}

at 300 K against a pressure of 100 kPa?

Q. Two moles of helium gas expanded isothermally and irreversible at

27^{0} C

1 d m^{3}

1 m^{3}

at a constant pressure of

100 K P a .

Calculate the work done.

Q. 2 moles of helium gas expanded isothermally and irreversible at

27

1 {d m}^{3}

1 m^{3}

at constant pressure of

100 k P a

. Calculate the work done.

Q. Three moles of an ideal gas kept at a constant temperature at

300 K

are compressed from a volume of

4 L

1 L

. The work done in the process is

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Introduction to Chemical Bonding

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon