CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The work function of a metal is 2 eV. If a radiation of wavelength 3000 ˚A is incident on it, the maximum kinetic energy of the emitted photoelectrons is :
(Planck's constant h=6.6×1034Js; Velocity of light c=3×108m/s;1eV=1.6×1019J)

A
4.4×1019J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
5.6×1019J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
3.4×1019J
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
2.5×1019J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 3.4×1019J
Energy of incident radiation is E=hcλ=6.6×1034×3×1083×107=6.6×1019 J.

Also, work function is ϕ=2×1.6×1019J=3.2×1019J.

Hence, maximum kinetic energy of emitted photo electrons will be 6.6×1019J3.2×1019J=3.4×1019J.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Emission and Absorption Spectra
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon