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Question

The work function of a photoelectric material is 4.0 eV. (a) What is the threshold wavelength ? (b) Find the wavelength of light for which the stopping potential is 2.5 V.


Solution

Φ=4 ev=4×1.6×1019J

(a) Threshold wavelength = λ

=hcΦ

=6.63×1034×3×1084×1.6×1019

=6.63×364×1027109

=3.1×107m

=310 nm

(b) Stopping potential is 2.5 V

E=Φ+eV

hcλ=4×1.6×1019+1.6×1019×2.5

λ=6.63×1034×3×1086.5×1.6×1019

=6.63×3×10261.6×1019×6.2

=1.9125×107190 nm

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