CameraIcon

CameraIcon

SearchIcon

MyQuestionIcon

MyQuestionIcon

Analysis of Force Equation

The work func...

Question

The work function of Ceasium is 2.14 electron volt. Find the wavelength of the incident light if the photo current is brought to zero by a stopping potential of 0.6 volt.

Open in App

Solution

Suggest Corrections

thumbs-up

0

BNAT

mid-banner-image

Similar questions

Q. Work function of caesium is

2.14 e V

. What is the wavelength of incident light if photocurrent is brought to zero by a stopping potential of

0.6 V

?

Q. Work function of caesium is

2.14 e V

. What is the wavelength of incident light if photocurrent is brought to zero by a stopping potential of

0.6 V

?

Q. The work function of caesium is 2.14 eV. Find a) the threshold frequency for caesium and b) the wavelength of the incident light if photocurrent is brought to zero by stopping potential of 0.60 V.

Q. Light of wavelength

0.6 μ m

from a sodium lamp falls on a photocell and causes the emission of photoelectrons for which the stopping potential is

0.5 V

. With light of wavelength

0.4 μ m

from a mercury vapor lamp, the stopping potential is

1.5 V

. Then, the work function [in electron volts] of the photocell surface is

Q. The work function of a metallic surface is 5.01 eV. The photo-electrons are emitted when light of wavelength

2000 \circ A

falls on it. The potential difference applied to stop the fastest photo-electrons is

[h = 4.14 \times 10^{- 15} e V s e c]

View More

Explore more

Analysis of Force Equation

Standard XII Physics