Question

The Young"s double slit experiment is performed with blue light and green light of wavelengths 4360 $A^o$ and 5460 $A^o$ respectively. If y is the distance of $4^{th}$ maximum from the central one, then

• A. $y_b=y_g$
• B. $y_b>y_g$
• C. $y_b<y_g$
• D. $\frac{y_b}{y_g}=\frac{5460}{4360}$

Answer 1

The correct option is C $y_b<y_g$

Given,

Wavelength of blue light, ${\lambda }_b=4360A^o$

Wavelength of green light, ${\lambda }_g=5460A^o$

Center distance of fourth bright fringe ${y^4}^{th}=n\lambda \frac{D}{d}$,

So, for constant D & d, $y\alpha \lambda$

As we know, ${\lambda }_b<{\lambda }_g$ ,

therefore $y_b<y_g$