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Question

The zeroes of the polynomial p(x)=(x−2)2−(x+2)2 is ____.

A
1
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B
x
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C
2
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Solution

p(x)=(x2)2(x+2)2
For zeroes of polynomial, put p(x)=0
(x2)2(x+2)2=0
[a2b2=(ab)(a+b)]
(x2+x+2)(x2x2)=0
2x(4)=0
8x=0
x=0
Hence, the zero of polynomial is 0.

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