The zeroes of the polynomial px-x2-3 x area 0-0b 0-3c 0-3d 3-3

(b) 0, 3 Let: px=x2 3x Now, we have: px=0 #8658;x2 3x=0 nbsp; nbsp; nbsp; nbsp; nbsp; #8658;xx 3=0 #8658;x=0 #160;and #160;x 3=0 #86 ...

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Standard IX

Mathematics

Zeroes of a Polynomial

The zeroes of...

Question

The zeroes of the polynomial p(x) = x² − 3x are
(a) 0, 0
(b) 0, 3
(c) 0, −3
(d) 3, −3

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Solution

(b) 0, 3

Let:
$p (x) = x^{2} - 3 x$
Now, we have:
$p (x) = 0 \Rightarrow x^{2} - 3 x = 0$
$\Rightarrow x (x - 3) = 0 \Rightarrow x = 0 and x - 3 = 0 \Rightarrow x = 0 and x = 3$

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The zeroes of the polynomial p(x) = x2 − 3x are (a) 0, 0 (b) 0, 3 (c) 0, −3 (d) 3, −3

(b) 0, 3 Let: px=x2-3x Now, we have: px=0⇒x2-3x=0 ⇒xx-3=0⇒x=0 and x-3=0⇒x=0 and x=3

The zeroes of the polynomial p(x) = x² − 3x are
(a) 0, 0
(b) 0, 3
(c) 0, −3
(d) 3, −3

(b) 0, 3

Let:
$p (x) = x^{2} - 3 x$
Now, we have:
$p (x) = 0 \Rightarrow x^{2} - 3 x = 0$
$\Rightarrow x (x - 3) = 0 \Rightarrow x = 0 and x - 3 = 0 \Rightarrow x = 0 and x = 3$