The zeroes of the polynomial x-2-x-12 are - -3- 43- -4-3- 42- 6

The correct option is C 3, 4 p(x)=0 ⇒ x^2 x 12=0 nbsp;x^2+3x 4x 12=0 ......(splitting the middle term) x(x+3) 4(x+3)=0 (x+3)(x 4)=0 x+3=0 ,(x 4)=0 ⇒ x= 3 ...

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Standard IX

Mathematics

Zeroes of a Polynomial

The zeroes of...

Question

The zeroes of the polynomial $x^{2} - x - 12$ are _, __.

3, 4

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3, - 4

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- 3, 4

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2, 6

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Solution

The correct option is C $- 3, 4$
$p (x) = 0 \Rightarrow x^{2} - x - 12 = 0$
$x^{2} + 3 x - 4 x - 12 = 0$ ......(splitting the middle term)
$x (x + 3) - 4 (x + 3) = 0$
$(x + 3) (x - 4) = 0$
$x + 3 = 0, (x - 4) = 0$
$\Rightarrow x = - 3, 4$

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Q. If α, β are the zeros of the polynomial (x² − x − 12), then form a quadratic equation whose zeros are 2α and 2β.

Q. The zeroes of the quadratic polynomial x² + x – 6 are __________.

Q. The zeroes of the polynomial

x^{2} - x - 12

are

3, 4.

Q. Question 2
A quadratic polynomial, who zeroes are -3 and 4, is
(a)

x^{2} - x + 12

(b)

x^{2} + x + 12

(c)

\frac{x^{2}}{2} - \frac{x}{2} - 6

(d)

2 x^{2} + 2 x - 24

The zeroes of the polynomial x2−x−12 are ___, ____.

The correct option is C −3,4 p(x)=0⇒x2−x−12=0 x2+3x−4x−12=0 ......(splitting the middle term) x(x+3)−4(x+3)=0 (x+3)(x−4)=0 x+3=0,(x−4)=0 ⇒x=−3,4

The zeroes of the polynomial $x^{2} - x - 12$ are _, __.

The correct option is C $- 3, 4$
$p (x) = 0 \Rightarrow x^{2} - x - 12 = 0$
$x^{2} + 3 x - 4 x - 12 = 0$ ......(splitting the middle term)
$x (x + 3) - 4 (x + 3) = 0$
$(x + 3) (x - 4) = 0$
$x + 3 = 0, (x - 4) = 0$
$\Rightarrow x = - 3, 4$