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Question

The zeros of the polynomial x2+16x2 are 

(a) -3, 4       (b) 32,43         (c) 43,32              (d) none of these


Solution

Polynomial :  x2+16x2


Comparing with the standard equation, we get


a = 1, b = 16  , c = -2


To find zero, equate it with 0


=> x2+16x2=0


Multiply by 6
=> 6x2+x12=0    
=> 6x2+9x8x12=0    ​​​​​​
=> 3x(2x+3)4(2x+3)=0
=> (2x+3)(3x4)=0
2x+3=0  Or 3x4=0
=> x = 32    or    43 
 so option b is correct


Mathematics
Secondary School Mathematics X
Standard X

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