Theoretical probability of an event A is given as $\frac{A}{B}$ where

S1 : A is the number of outcomes favourable to E

S2 : B is the total number of possible outcomes.

S1 and S2 are false

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S1 and S2 are true

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S1 is true and S2 is false

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S1 is false and S2 is true

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Solution

The correct option is B
S1 and S2 are true

Theoretical probability = $\frac{n u m b e r o f o u t c o m e s f a v o u r a b l e t o e v e n t E}{t o t a l n u m b e r o f p o s s i b l e o u t c o m e s}$

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STATEMENT-1 - A point particle of mass m moving with speed v collides with stationary point particle of mass M. If the max energy loss possible is given as f(mv²/2), then f=(m/M+m).

STATEMENT-2 - Max energy loss occurs when the particles get stuck together as a result of the collision.

A) Both S1 and S2 are true, S2 explains S1 correctly

B) Both S1 and S2 are true, S2 does not explain S1

C) S2 is false, S1 is true

D) S1 is false, S2 is true

Explain in detail.

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Theoretical probability of an event A is given as AB where S1 : A is the number of outcomes favourable to E S2 : B is the total number of possible outcomes.

The correct option is B S1 and S2 are true Theoretical probability = number of outcomes favourable to event Etotal number of possible outcomes

Theoretical probability of an event A is given as $\frac{A}{B}$ where

S1 : A is the number of outcomes favourable to E

S2 : B is the total number of possible outcomes.

The correct option is B
S1 and S2 are true

Theoretical probability = $\frac{n u m b e r o f o u t c o m e s f a v o u r a b l e t o e v e n t E}{t o t a l n u m b e r o f p o s s i b l e o u t c o m e s}$