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Question

There are 20% adenines among the bases in a DNA fragment measuring 6.8 nm in length. The number of pentose, nitrogen base pairs, phosphate groups and hydrogen bonds in this DNA fragment are respectively.

A
52,20,20,40
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B
40,52,40,20
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C
20,40,52,40
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D
40,20,40,52
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Solution

The correct option is D 40,20,40,52
Here, the given DNA measure = 6.8nm = 68 Angstroms.
Length of DNA = Distance between base pairs × Total number of base pairs
Therefore, 68 ˚A = 3.4˚A × Total number of nitrogen base pairs.
Hence, nucleotides = 40
1 nucleotide = 1 nitrogen base + 1 pentose sugar + 1 phosphate groups
So, pentose sugar = 40
Phosphate groups = 40
From the percent mentioned these are 8 combinations of A-T and 12 combinations of C=G in given fragment of DNA. Adenine is paired to thymine by two hydrogen bonds and cytosine is paired to guanine by three hydrogen bonds.
So 8× 2 = 16 and 12 × 3 = 36
16+ 36 = 53 hydrogen bonds.

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