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Question

There are 3 men and 7 women taking a dance class. If N is number of different ways in which each man be paired with a woman partner, and the four remaining women be paired into two pairs each of two, then the value of N90 is 


Solution

The required men and women pair can be made in 7P3 ways
and from 4 womens two groups can be made in 4!2!2!2! ways
So total number of ways N=210×3=630
N90=7

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