Question

There are 30 tickets numbered from 1 to 30 in a box. A ticket is drawn. What is the probability that the ticket drawn

(ii) bears as number which is a perfect square.

Answer 1

Let S be the sample space.
∴ S = {1, 2, 3, 4,..., 30}
Or,
n(S) = 30
Now,
Let B be the event that the ticket drawn bears a number that is a perfect square.
∴ B = {1, 4, 9, 16, 25}
Or,
n(B) = 5
Thus, we have:
P(B) = $\frac{n\left(B\right)}{n\left(S\right)}=\frac{5}{30}=\frac{1}{6}$
∴ Probability that the ticket drawn bears a number that is a perfect square = $\frac{1}{6}$