Question

There are 5 different caps $c_1,c_2,c_3,c_{4}and{c}_5$ and 5 different boxes $B_1,B_2,B_3,B_{4}and{B}_5$. The capacity of each box is sufficient to accomodate all the 5 caps.

If all the caps are identical, in how many ways can the caps be arranged in the different boxes such that no box is empty?

• A. 1
• B. 2
• C. 6
• D. 8

Answer 1

The correct option is A 1

Since all the boxes are filled with exactly one cap and all the caps are identical. Hence the required number of ways = 1.