Question

# There are 6 red and 5 black balls in a bag. A ball is drawn from the bag at random and without replacing it an other ball is drawn at random. The probability that both the balls drawn may be red is

A
211
B
311
C
611
D
511

Solution

## The correct option is D $$\displaystyle \frac{3}{11}$$A bag contains: $$6R + 5B = 11$$Probability of getting $$1R + 1R$$ ball from this bag without replacement:$$= (\dfrac{6}{11})\times(\dfrac{5}{10})=\dfrac{3}{11}$$Mathematics

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