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Question

There are 6 red and 5 black balls in a bag. A ball is drawn from the bag at random and without replacing it an other ball is drawn at random. The probability that both the balls drawn may be red is


A
211
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B
311
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C
611
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D
511
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Solution

The correct option is D $$\displaystyle \frac{3}{11}$$
A bag contains: $$6R + 5B = 11$$
Probability of getting $$1R + 1R$$ ball from this bag without replacement:
$$= (\dfrac{6}{11})\times(\dfrac{5}{10})=\dfrac{3}{11}$$

Mathematics

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