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Question

There are 8 brown balls, 4 oragne balls and 5 black balls in a bag. Five balls are chosen at random. What is the probability of there being 2 brown balls, 1 orange ball and 2 black balls?


A
1911547
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B
1801547
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C
2801547
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D
1801547
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E
None of these
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Solution

The correct option is C 2801547
Toal possible outcomes =17C5
=17×16×15×14×131×2×3×4×5=6188
Total favourable outcomes =8C2×4C1×5C2
=8×71×2×4×5×41×2=28×4×10=1120
Required probability =11206188=2801547
 

Quantitative Aptitude

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