Question

# There are 8 brown balls, 4 oragne balls and 5 black balls in a bag. Five balls are chosen at random. What is the probability of there being 2 brown balls, 1 orange ball and 2 black balls?

A
1911547
B
1801547
C
2801547
D
1801547
E
None of these

Solution

## The correct option is C 2801547Toal possible outcomes =17C5 =17×16×15×14×131×2×3×4×5=6188 Total favourable outcomes =8C2×4C1×5C2 =8×71×2×4×5×41×2=28×4×10=1120 Required probability =11206188=2801547  Quantitative Aptitude

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