Question

There are $$8$$ points in a plane out of which $$4$$ are collinear. How many triangles can be formed with these these points as vertices?

A
52
B
56
C
48
D
54

Solution

The correct option is A $$52$$There are $$4$$ points collinear. There would be $$3$$ cases1. Choose any three points from $$4$$ non - collinear points.2. Choose any $$2$$ points from $$4$$ non collinear and $$1$$ point from collinear points.3. Choose any $$2$$ points from $$4$$  collinear and $$1$$ point from  non -collinear points.Total number of ways $$=^4C_3$$ $$+^4C_1 \times ^4C_2$$ + $$4^C_1 \times ^4C_2$$$$=52$$Maths

Suggest Corrections

0

Similar questions
View More

People also searched for
View More