There are four solutions of NaCl of the given concentrations :
(i) 1.0M(ii) 0.1M(iii) 0.01M(iv) 0.5M
The correct order of this equivalent conductances

i> ii > iv > iv

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i> iv > ii > iii

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ii > iii > iv >i

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iii > ii > iv >i

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Solution

The correct option is D
iii > ii > iv >i

Higher the normality, lower its equivalent conductance

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Similar questions

Which of the following options represent their correct order of equivalent conductance?

+ I

- C H_{3}

- C D_{3}

- C T_{3}

- C H D_{2}

- I

- C N

- N O_{2}

- N H_{2}

- F

Arrange them in decreasing order of the weight of oxygen

i) 4.0g of $N a O H$ ii) 4.8g of $S O_{2}$

iii) 4.0 g of $C O_{2}$ iv)2.8 g of $C a O$

In the species

i) 4.0g of $N a O H$ ii) 4.8g of $S O_{2}$

iii) 4.0 g of $C O_{2}$ iv) 2.8 g of $C a O$ ,

decreasing order of the weight of oxygen is

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