There are three stations $A, B$ and $C$ , five routes for going from station $A$ to station $B$ and four routes for going from station $B$ to station $C$ .
Find the number of different ways through which a person can go from station $A$ to $C$ via $B$

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Solution

The correct option is B 20
Since there are five routes for going from station A to station B
So number of ways of going from A to B is $5$
And there are four routes for going from B to C, so the number of ways of going from B to C is $4$
Thus using multiplication rule, number of ways of going from A to C via B is, $5 \times 4 = 20$

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There are three stations A, B and C, five routes for going from station A to station B and four routes for going from station B to station C.Find the number of different ways through which a person can go from station A to C via B

There are three stations $A, B$ and $C$ , five routes for going from station $A$ to station $B$ and four routes for going from station $B$ to station $C$ .
Find the number of different ways through which a person can go from station $A$ to $C$ via $B$