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Question

There are two bulbs filled with an ideal gas. Bulb 1 has a volume of 5 L and a pressure of 9 atm, bulb 2 has a volume of 10 L and a pressure of 6 atm. When these bulbs are connected, what is the final pressure if the temperature remains constant?

A
15 atm
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B
7 atm
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C
12 atm
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D
21 atm
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Solution

The correct option is B 7 atm
Now as the question says temperature is constant which let's us to use Boyle's law
For Bulb 1:
Product of pressure and volume (PV)1 = (5 L)(9 atm)
=45 atm L

For Bulb 2:
Product of pressure and volume (PV)2= (10 L)(6 atm)
=60 atm L

Now when bulbs are connected the total volume will be 5L+10L =15 L = V3 and the new pressure will be obtained by summing up the products of pressure and volume of two bulbs.
i.e. (PV)3 = (PV)1+ (PV)2
P3=5×9+10×615 atm
=7 atm

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