Question

There are two cars of which one holds not more than $5$ and the other not more than $4$. The number of ways can a party of $8$ people go for excursion in the two cars is

• A. $8400$
• B. $126$
• C. $124$
• D. $6400$

Answer 1

Answer: (B)

$126$

No. of ways ${=}^8{C}_5{\times }^3{C}_3{+}^8{C}_4{\times }^4{C}_4{=}^9{C}_5$

No. of ways ${=}^9{C}_5{=}^9{C}_4=126$ $ways$