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Question

There are two holes one each along the opposite sides of a wide rectangular tank. The cross section of each hole is $$0.01m^{2}$$ and the vertical distance between the holes is one meter. The tank is filled with water. The net force on the tank in Newton when water flows out of the holes is: (Density of water $$1000kg/m^{3}$$)


A
100
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B
200
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C
300
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D
400
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Solution

The correct option is A $$200$$
force  of  the  tank  is $$ \dfrac{d}{dt} (mv)$$
$$ = \dfrac{dm}{dt} .v$$
$$ = \dfrac{d (sAh)}{dt} .v$$
$$ = s A v^{2}$$
$$ = 1000 \times 0.01 \times (\sqrt{2gh})^{2}$$
$$ = 1000 \times 0.01  \alpha   2 \times  10 \times 1$$
$$ = 200.N$$

Physics

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