There is a circular tube in a vertical plane- Two liquids which do not mix and of densities d 1 and d 2 are filled in the tube- Each liquid subtends 90- angle at the centre- Radius joining their interface makes an angle -30- with vertical- Ratiod1d2 is Answer upto two digit after the decimal point

Equating pressure at A, (Rcos nbsp;α nbsp;+ nbsp;Rsin nbsp;α) nbsp;d2g nbsp;= nbsp;(Rcos nbsp;α nbsp; nbsp;Rsin nbsp;α) nbsp;d1g ⇒d1d2 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Elevation in Boiling Point

There is a ci...

Question

There is a circular tube in a vertical plane. Two liquids which do not mix and of densities $d_{1}$ and $d_{2}$ are filled in the tube. Each liquid subtends $90^{o}$ angle at the centre. Radius joining their interface makes an angle $α = 30^{o}$ with vertical. Ratio $\frac{d_{1}}{d_{2}}$ is (Answer upto two digit after the decimal point)

Open in App

Solution

Equating pressure at A,
$(R cos α + R sin α) d_{2} g = (R cos α - R sin α) d_{1} g$
$\Rightarrow \frac{d_{1}}{d_{2}} = \frac{cos α + sin α}{cos α - sin α} = \frac{1 + tan α}{1 - tan α} = \frac{\sqrt{3} + 1}{\sqrt{3} - 1} = 3.732$

Suggest Corrections

Similar questions

There is a circular tube in a vertical plane. Two liquids which do not mix and of densities $d_{1}$ and $d_{2}$ are filled in the tube. Each liquid subtends $90^{\circ}$ angle at centre. Radius joining their interface makes an angle $α$ with vertical. Ratio of $\frac{d_{1}}{d_{2}}$ is