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Question

There is a grouped data distribution for which mean is to be found by step deviation method.

Class IntervalNumber of Frequency(fi)Class mark(xi)di=xiaui=dih01004050200D......10020039150B.....E.....200300342500030040030350100140050045450C.....F......TotalA=fi=......

Find the value of  A, B, C, D, E and F respectively.



A

188 , -100, 200, -2 ,-1 and 2

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B

186 , 100, -200, -2 ,-1 and 2

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C

188 , 100, -200, 2 ,-1 and -2

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D

186 , -100, -200, -2 ,-1 and 2

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Solution

The correct option is A

188 , -100, 200, -2 ,-1 and 2


fi= sum of frequencies of each class
        = 40 + 39 + 34 + 30 + 45
        = 188
A=188

Now, di=xia

where,
xi is ith row class mark and 'a' is assumed mean.

Using above formula for 1st class (0-100) we get:

200=50aa=250 and class size h=100

Using the above information, lets complete the table,.
Class IntervalNumber of Frequency(fi)Class mark(xi)di=xiaui=dih0100405020021002003915010012003003425000300400303501001400500454502002TotalA=fi=188

Thus,A, B, C, D, E and F are 188,100,200,2,1 and 2 respectively.


Mathematics

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