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Question

There is a pyramid on a base which is a regular hexagon of side 2a. If every slant edge of this pyramid is of length (5a)2, then the volume of this pyramid must be

A
3a3
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B
3a32
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C
3a33
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D
6a3
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Solution

The correct option is C 3a33

Side of regular hexagon =2a cm
ar. of hexagon =6×34×2a×2a=63a2
Slant height of pyramid =5a2cm=AG
h=(5a2)2(2a)2=3a2
Volume of pyramid =13×ar.base×h
=13×63a2×3a2
=33a3cm3

960803_299300_ans_37ff9032be764cff8ce473e2ed84b5f7.jpg

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